C^4+7c^2+12=0

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Solution for C^4+7c^2+12=0 equation: 



^4+7C^2+12=0

We add all the numbers together, and all the variables

7C^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$C=\frac{-b}{2a}=\frac{0}{14}=0$

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